(x^2-x-2)(4x+5)=0

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Solution for (x^2-x-2)(4x+5)=0 equation: 


Simplifying
(x2 + -1x + -2)(4x + 5) = 0

Reorder the terms:
(-2 + -1x + x2)(4x + 5) = 0

Reorder the terms:
(-2 + -1x + x2)(5 + 4x) = 0

Multiply (-2 + -1x + x2) * (5 + 4x)
(-2(5 + 4x) + -1x * (5 + 4x) + x2(5 + 4x)) = 0
((5 * -2 + 4x * -2) + -1x * (5 + 4x) + x2(5 + 4x)) = 0
((-10 + -8x) + -1x * (5 + 4x) + x2(5 + 4x)) = 0
(-10 + -8x + (5 * -1x + 4x * -1x) + x2(5 + 4x)) = 0
(-10 + -8x + (-5x + -4x2) + x2(5 + 4x)) = 0
(-10 + -8x + -5x + -4x2 + (5 * x2 + 4x * x2)) = 0
(-10 + -8x + -5x + -4x2 + (5x2 + 4x3)) = 0

Combine like terms: -8x + -5x = -13x
(-10 + -13x + -4x2 + 5x2 + 4x3) = 0

Combine like terms: -4x2 + 5x2 = 1x2
(-10 + -13x + 1x2 + 4x3) = 0

Solving
-10 + -13x + 1x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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